Question

The volume of gas in a balloon is 1.90L at 21.0°C.The balloon is heated, causing it to expand to a volume of 5.70L. what is the new temperature of the gas inside the balloon?

Answer 1

Answer: The new temperature is
`63^(o)C`.

Step-by-step explanation:

Given:
`V_(1)` = 1.90 L,
`T_(1) = 21.0^(o)C`

`V_(2)` = 5.70 L,
`T_(2) = ?\\`

Formula used to calculate new temperature is as follows.

`(V_(1))/(T_(1)) = (V_(2))/(T_(2))`

Substitute the values into above formula as follows.

`(V_(1))/(T_(1)) = (V_(2))/(T_(2))\\(1.90 L)/(21.0^(o)C) = (5.70 L)/(T_(2))\\T_(2) = 63^(o)C`

Thus, we can conclude that the new temperature is
`63^(o)C`.