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9 votes
9 votes
Find the 6th term of the geometric sequence whose common ratio is 3/2 and whose first term is 5

User Gilletty
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1 Answer

28 votes
28 votes

Answer:

a(6) = 37.97

Explanation:

If the first term a(1) is 5 and the common ratio r is 3/2, then the general formula for this geometric sequence is

a(n) = 5*r^(n - 1).

Thus, the 6th term is a(6) = 5*(3/2)^(6 - 1), or a(6) = 5(3/2)^5 = 37.97

User Alysson Myller
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3.7k points