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In this diagram, radius AD = 5 mm, radius BD = 12 mm and chord

CD = 8 mm. Find the exact length of AB, in surd form.

In this diagram, radius AD = 5 mm, radius BD = 12 mm and chord CD = 8 mm. Find the-example-1

2 Answers

4 votes

The exact length of AB=5 + 6√2 mm

To find the length of AB in surd form, we will use the Power of a Point Theorem (also known as the chord-chord product theorem), which states that for two chords intersecting inside a circle, the products of the lengths of the segments of each chord are equal.

Given:

AD = 5 mm

BD = 12 mm

CD = 8 mm

We need to find AB.

We can find the length of AC first, because AC and CD are parts of the same chord, and we have that AC + CD = AD + BD (since A, B, D are collinear points on the same circle). This gives us:

AC + 8 = 5 + 12

Now, solving for AC:

AC = 17 - 8

AC = 9 mm

Using the Power of a Point Theorem, we set the product of the lengths of one chord (AC and CD) equal to the product of the lengths of the other chord (AD and the unknown segment DB, which we can call x):

AC * CD = AD * DB

(AC) * (CD) = (AD) * (x + AD)

Substituting the known lengths:

9 * 8 = 5 * (x + 5)

Solving for x (the length of segment DB):

72 = 5x + 25

5x = 72 - 25

5x = 47

x = 47/5

x = 9.4 mm

The length of AB is the sum of AD and DB:

AB = AD + DB

AB = 5 + 9.4

AB = 14.4 mm

Therefore, the exact length of AB is 14.4 mm. However, since we want the length in surd form, and we used a calculated value of AC (which should have been derived using the Power of a Point Theorem), we should re-evaluate this calculation in surd form.

To do this correctly, let's apply the Power of a Point Theorem, taking into account that the length of DB is the length of BD minus the length of AD:

AC * CD = AD * (BD - AD)

9 * 8 = 5 * (12 - 5)

72 = 5 * 7

72 = 35

Now, we will express the length of AB (which is the sum of AD and BD minus AD) in surd form:

AB = AD + (BD - AD)

AB = 5 + sqrt(72)

AB = 5 + sqrt(36 * 2)

AB = 5 + 6 * sqrt(2)

AB = 5 + 6√2 mm

User Emmily
by
8.0k points
2 votes

Answer:

The exact length of AB is
3 + 4√(10) milimeters.

Explanation:

Both triangles ACD and BCD are isosceles and triangles AEC, ADE, BDE and BCE are right-angled, where E is the point where line segments AB and CD meet each other. We can determine the exact length of AB by means of two horizontal right triangles (i.e. AEC, BCE) and the Pythagorean Theorem:


AB = \sqrt{AC^(2)-CE^(2)}+\sqrt{CB^(2)-CE^(2)}

If we know that
AD = AC,
BC = BD,
AC = 5\,mm,
BC = 12\,mm and
CE = 4\,mm, then the exact length of AB is:


AB = \sqrt{(5\,mm)^(2)-(4\,mm)^(2)}+\sqrt{(12\,mm)^(2)-(4\,mm)^(2)}


AB = 3 + 4√(10)\,[mm]

User Hemant Rao
by
7.1k points