Question

A. how many grams of H2SO4 are in 3.5 liters of 2.0 M H2SO4

b. how many liters of 2.0 M H2SO4 would be made from 3 liters of water. (Hint water has a density of 1g per mL.)

Answer 1

a. 686g of H2SO4 are present.

b. 3.321L would be made

Step-by-step explanation:

a. Molarity, M, is an unit of concentration defined as the ratio between moles of solute (In this case H2SO4) and liters of solution. The moles of H2SO4 in 3.5L of 2.0M H2SO4 are:

3.5L * (2.0mol H2SO4 / L) = 7.0 moles H2SO4

The mass is obtained using molar mass of H2SO4 -98g/mol-:

7.0 moles H2SO4 * (98g / mol) = 686g of H2SO4 are present

b. The density of H2SO4 is 1.83g/mL. The volume of 2.0M H2SO4 per liter of solution is:

2.0mol H2SO4 / L * (98g / mol) * (1mL / 1.83g) = 107mL of H2SO4 are present per liter of solution. In 3L there are:

3L (107mL / L) = 321mL = 0.321L of H2SO4 must be added to 3L of water to produce 2.0M H2SO4. The total volume is:

3L + 0.321L = 3.321L would be made