Question

(give the answer or I'll report) please solve it with the steps​

Answer 1

The required elastic potential energy is 0.068J

Step-by-step explanation:

Given,

Spring force constant, k= 3.4 N/M

Spring stretch length/ Displacement, x= 0.2m

We know,

Elastic potential energy, V=
`(1)/(2) kx^(2)`

=
`(1)/(2)*3.4*(0.2)^(2)`

=
`(0.136)/(2)`

=0.068

∴The required elastic potential energy is 0.068J