465,213 views
15 votes
15 votes
Find the area of the larger sector.
6 in
O 30°

Find the area of the larger sector. 6 in O 30°-example-1
User Milgo
by
2.7k points

1 Answer

12 votes
12 votes
Answer:=103.67in^2

Explanation:
Sector area= r^2×a/2
. =36×0.5233 /2
Asector= 9.42in^2
Area of circle= πr^2
. =3.14×36
area of circle = 113.097in^2
Area of larger sector = area of circle- area of Sector
Area of larger sector
=113.097in^2 - 9.42in^2
=103.67in^2

User Dave Konopka
by
2.4k points