Answer:
2.675 moles of Chlorine gas are required
Step-by-step explanation:
Chlorine gas, Cl2, reacts with NaBr to produce NaCl and Br2 as follows:
Cl2 + 2NaBr → 2NaCl + Br2
Where 1 mole of chlorine gas produce 2 moles of NaCl
Thus, to produce 5.35 moles of NaCl are required:
5.35mol NaCl * (1mol Cl2 / 2mol NaCl) =
2.675 moles of Chlorine gas are required