Question

What is the temperature of 0.750 mol of a gas stored in a 6,050 mL cylinder al 221 atm?

atm
Use and
molek
5.24K
138 K
246 K

Answer 1

T = 246 K

Step-by-step explanation:

Given that,

Number of moles, n = 0.750 mol

The volume of the cylinder, V = 6850 mL = 6.85 L

Pressure of the gas, P = 2.21 atm

We need to find the temperature of the gas stored in the cylinder. We know that,

PV= nRT

Where

R is gas constant

T is temperature

So,

`T=(PV)/(nR)\\\\T=(2.21* 6.85)/(0.75* 0.0821)\\T=245.85\ K`

or

T = 246 K

So, the temperature of the gas is equal to 246 K.