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Find the area of the larger sector.
6 in
O 30°

Find the area of the larger sector. 6 in O 30°-example-1

1 Answer

8 votes
Answer:=103.67in^2

Explanation:
Sector area= r^2×a/2
. =36×0.5233 /2
Asector= 9.42in^2
Area of circle= πr^2
. =3.14×36
area of circle = 113.097in^2
Area of larger sector = area of circle- area of Sector
Area of larger sector
=113.097in^2 - 9.42in^2
=103.67in^2

User DimChtz
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