Question

Please helppppppp!!!!!!

Answer 1

The resulting force on the first object is 800 N.

Step-by-step explanation:

Given;

force exerted on one of the objects, F₁ = 400 N

let the first charge = q₁

let the second charge = q₂

The force of repulsion between the objects is calculated using Coulomb's law;

`F =(kq_1q_2)/(r^2) \\\\(k)/(r^2) = (F)/(q_1q_2) = (F_1)/(q_1*2q_2) \\\\F_1 = (F(q_1*2q_2))/(q_1q_2) \\\\F_1 = 2F\\\\F_1 = 2(400 \ N)\\\\F_1 = 800 \ N`

Therefore, the resulting force on the first object is 800 N.