Question

If a spinner for a game is spun once, there is a 25% chance it will land on

orange. What is the chance that the spinner will not land on orange on both
the first and second spin in a game? Calculate the probability as a decimal
rounded to the nearest TENTH.

Answer 1

`Pr = 0.6`

Explanation:

Given

Let

`O \to Orange`

So:

`P(O) = 25\%` --- probability of O

`n=2` --- Number of spin

Using the complement rule, the probability that a spin will not land on orange is:

`P(O') = 1 - P(O)`

`P(O') = 1 - 25\%`

Express as decimal

`P(O') = 1 - 0.25`

`P(O') = 0.75`

On two spins, the probability that it will not land on orange is:

`Pr = P(O') * P(O')`

So, we have:

`Pr = 0.75* 0.75`

`Pr = 0.5625`

`Pr = 0.6` --- approximated