Question

Find the 6th term of the geometric sequence whose common ratio is 3/2 and whose first term is 5

Answer 1

a(6) = 37.97

Explanation:

If the first term a(1) is 5 and the common ratio r is 3/2, then the general formula for this geometric sequence is

a(n) = 5*r^(n - 1).

Thus, the 6th term is a(6) = 5*(3/2)^(6 - 1), or a(6) = 5(3/2)^5 = 37.97