Answer:

Explanation:
Since we want to find the distance between a pair of points, we use the following formula:

Where (x₁, y₁) and (x₂, y₂) are the points.
We are given the points E (-5, 4) and F (6,4). If we match the values and corresponding variables, we see that:
Substitute the values into the formula.

Solve inside the parentheses.
- (6--5)= (6+5)=11
- (4-4)= 0

Solve the exponents.
- (11)²= 11*11= 121
- (0)²= 0*0= 0

Add.

Solve the square root.

The distance between the 2 points is 11.