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What are the solutions to the quadratic equation x2-16=0

User Anubis
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1 Answer

3 votes

Answer:

x = -4, 4

Explanation:

Hi there!


x^2-16=0

Rewrite 16:


x^2-4^2=0

The difference of squares rule states that
a^2-b^2=(a+b)(a-b). With this, apply the difference of squares to the equation:


(x+4)(x-4)=0

The zero-product property states that if the product of two numbers is 0, then one of the numbers must be equal to zero. Set each term equal to 0 and find the solutions:


x+4=0\\x=-4


x-4=0\\x=4

Therefore, the solutions are -4 and 4.

I hope this helps!

User Masako
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