Question

Two ships leave a harbor at the same time. One ship travels on a bearing S14°W at 15 miles per hour. The other ship travels on a bearing N75°E at 11 miles per hour. How far apart will the ships be after 3 hours?

Answer 1

67.48 miles

Explanation:

the angle between two ships =180°-75°+14°= 119°

the first ship travels for 15×3=45miles

the second ship trave 11×3=33miles

the distance between them after 3 hours=

√(45²+33³-2(45)(33)cos 119°)

=√(2025+1089+1440)

=√4554

= 67.48 miles