Question

How many mL of a 6 M NaOH stock solution is needed in order to prepare 500 mL of a 0.2 M NaOH solution?

Answer 1

The right answer is "16.67 mL".

Step-by-step explanation:

Given:

Molarity of NaOH,

`M_1=6 \ M`

`M_2=0.2 \ M`

Volume of NaOH,

`V_1=V \ mL`

`V_2=500 \ mL`

As we know, the equation,

⇒
`M_1V_1=M_2V_2`

On putting the values, we get

⇒
`6* V=0.2* 500`

⇒
`6* V=100`

⇒
`V=(100)/(6)`

⇒
`=16.67 \ mL`