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What is the pOH of a solution with an OH- ion concentration of

6.0E-4?

User Anthney
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1 Answer

5 votes

Final answer:

The pOH of a solution with an OH- ion concentration of 6.0E-4 is 3.22, calculated by taking the negative log of the hydroxide ion concentration.

Step-by-step explanation:

To calculate the pOH of a solution with an OH- ion concentration of 6.0E-4, you take the negative logarithm of the hydroxide ion concentration. Doing so, you get:

pOH = -log [OH-]

pOH = -log(6.0 × 10-4)

pOH = 3.22

That's the pOH of the solution. To find the pH, you would subtract the pOH from 14 (since pH + pOH = 14 for any aqueous solution at 25°C), but since the question only asks for pOH, that additional calculation isn't necessary here.

User Enguerranws
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8.4k points
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