Question

What is the equation in slope-intercept form of the line that passes through the points (-17, -16) and (0, -13)?

Answer 1

Answer:
`y=(3)/(17)x-13`

Explanation:

Find the slope of the line between (-17, -16) and (0,-13) using
`m=(y_(2)-y_(1) )/(x_(2)-x_(1) )`, the change of y over the change of x

`m=(3)/(17)`

Use the slope and a given point to substitute for
`x_(1)` and
`y_(1)` in the point-slope form
`y-y_(1) =m(x-x_(1) )`.

`y-(-16)=(3)/(17)(x+17)`

Solve for y and rewrite into
`y=mx+b`

`y=(3)/(17)x-13`