Question

Three resistors of values 2 Q, 3 Q and 5 Q are connected in series with a battery of voltage 6.0 V. Calculate the current through each of the resistors, and the current through the battery.

Answer 1

Current = 0.6 A

Step-by-step explanation:

Given that,

Three resistors 2 ohms, 3 ohms and 5 ohms are connected in series with a battery of voltage 6 V.

In series combination of resistors, the current through each resistor is the same while the voltage divides.

The equivalent resistance in this case is given by :

`R_(eq)=R_1+R_2+....`

Put all the values,

`R_(eq)=2+3+5\\\\R_(eq)=10\ \Omega`

Let I be the current. Using Ohm's law,

`V=IR\\\\I=(V)/(R)\\\\I=(6)/(10)\\\\I=0.6\ A`

So, the current through each resistor and the current through the battery is equal to 0.6 A.