Question

It takes 38.5mL of 0.753M NaOH solution to completely neutralize 155mL of a sulfuric acid. What is the concentration of the sulfuric acid?

Answer 1

The correct solution is "93.48 M".

Step-by-step explanation:

According to the question,

The number of moles of NaOH will be:

=
`0.753* 38.5`

=
`28.99 \ mol`

The number of moles of needed
`H_2SO_4` will be:

=
`(1)/(2)* 28.99`

=
`14.49 \ mol`

hence,

The concentration of
`H_2SO_4` solution will be:

=
`(Number \ of \ moles)/(Volume \ of \ solution)`

=
`(14.49)/(0.155)`

=
`93.48 \ M`