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Recall the equation for a circle with center ( h , k ) and radius r . At what point in the first quadrant does the line with equation y = 2.5 x + 4 intersect the circle with radius 5 and center (0, 4)?

User Jshort
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Answer: The required point = (1.857,8.643)

Explanation:

Equation of circle with center (h,k) and radius r:
(x-h)^2+(y-k)^2=r^2

Given: Radius = 5 , center = (0,4)

Eqation of circle:
(x-0)^2+(y-4)^2=5^2


x^2+(y-4)^2=25


x^2+(2.5x+4-4)^2=25 [Using equation y = 2.5 x + 4 ]


x^2+(2.5x)^2=25


x^2+6.25x^2=25


7.25x^2=25


x^2=3.44827586207


x=1.857


y= 2.5(1.857)+4


=8.6425

Hence, the required point = (1.857,8.643)

User LiMar
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