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Mrs. Giavis has 26 marbles in a bag. She has 13 blue marbles, 10 red marbles, and 3 yellow marbles. What is the probably that Mrs. Giavis will pick a blue marble, not replace it, and then randomly pick a red marble?

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Given:

Total number of marbles = 26

Number of blue marbles = 13

Number of red marbles = 10

Number of yellow marbles = 3

To find:

The probability of getting a blue marble then a red marble (without replacement).

Solution:

Total number of marbles = 26

Number of blue marbles = 13

Probability of getting a blue marble is first draw is:


P(Blue)=\frac{\text{Number of blue marbles}}{\text{Total number of marbles}}


P(Blue)=(13)/(26)


P(Blue)=(1)/(2)

After drawing 1 marble, the remaining number of marbles in the bag is 25.

Probability of getting a red marble is second draw is:


P(Red)=\frac{\text{Number of red marbles}}{\text{Remaining number of marbles}}


P(Red)=(10)/(25)


P(Red)=(2)/(5)

Now the probability of getting a blue marble then a red marble (without replacement) is:


P(\text{Blue then red})=P(Blue)* P(Red)


P(\text{Blue then red})=(1)/(2)* (2)/(5)


P(\text{Blue then red})=(1)/(5)

Therefore, the probability of getting a blue marble then a red marble (without replacement) is
(1)/(5).

User Chris Thornton
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