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Two identical thermally insulated spherical tanks, A and B, are connected by a valve. Initially tank A contains 20mol of an ideal diatomic gas, tank B is evacuated, and the valve is closed.

If the valve is opened and the gas expands isothermally fromA to B, what is the change in the entropy of the gas?

User Whyser
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2 Answers

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Final answer:

The change in entropy for an ideal diatomic gas expanding isothermally into an evacuated tank is calculated using the formula ΔS = nRln(Vf/Vi), which yields a positive value indicating spontaneous and irreversible expansion.

Step-by-step explanation:

The question at hand relates to the concept of entropy change during an isothermal expansion of an ideal diatomic gas into a vacuum. Since work is defined as the product of pressure and volume change and the pressure in a vacuum is zero, no pressure-volume work is done when the gas expands into the evacuated tank. However, even without external work, there is a change in the entropy of the gas because the number of microstates of the system increases when the gas expands from tank A to tank B.

The entropy change (ΔS) for an isothermal expansion can be calculated using the formula:

ΔS = nRln(Vf/Vi)

Where n is the number of moles of the gas, R is the ideal gas constant, and Vf and Vi are the final and initial volumes, respectively. Since tank B is initially evacuated, and tanks A and B are identical, the final volume of the gas would be twice the initial volume. Therefore, the entropy change would be positive and the expression simplifies to:

ΔS = 20mol * R * ln(2)

In conclusion, the entropy of the gas increases as it expands from tank A to tank B, indicating that the process is spontaneous and irreversible.

User Barry Rosenberg
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Answer:

Step-by-step explanation:

Volume of gas is doubled isothermally . Let the temperature of the gas be T .Work done by the gas

W = 2.303 nRT log 2 V / V

Since expansion is isothermal , Δ E = 0

Q = ΔE + W

Q = W

Q = 2.303 nRT log 2 V / V

Q / T = 2.303 n R log 2

Change in entropy = ΔS = Q / T = 2.303 n R log 2

= 2.303 x 20 x 8.3 x .3010 J T⁻¹.

= 115 J T⁻¹.

User Naveed Butt
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