Answer:
There are at least 7 M&M's in the bag, since if there were only 1 green M&M, there would be 2.5 blue M&Ms, which is impossible.
Explanation:
Given that the ratio of green M&M's to yellow is 2: 5, if there are only green and yellow M&M's in the bag, to determine what is the smallest number of M&M's possible, the following calculation must be performed:
5/2 = 2.5
2/5 = 1 / 2.5
Therefore, there are at least 7 M&M's in the bag, since if there were only 1 green M&M, there would be 2.5 blue M&Ms, which is impossible.