Question

A bowling ball moving with a velocity of 5V to the right collides elastically with a beach ball moving at a velocity 2V to the left. The bowling ball barely slows down. What is the approximate velocity of the beach ball after the collision?

Answer 1

`v'_2=3V`

Step-by-step explanation:

From the question we are told that:

Bowling ball Speed
`v_1=5 m/s`

Beach ball Speed
`v_2=2 m/s`

Let The Mass be equal i.e

`M_1=M_2`

Therefore

Generally the equation for Velocity of beach ball after collision
`v'_2` is mathematically given by

Since Velocity is Vector Quantity

Therefore

`v'_2=v_1-v_2`

`v'_2=5-2`

`v'_2=3V`