Question

Can somebody help me with writing a real-life problem on this subject Finding angle measures of a right or isosceles triangle given angles with variables thank you?

Answer 1

See Explanation

Explanation:

See attachment for illustration

(a) Right triangle

The sum of
`angles` in a
`right`
`triangle`is:

`x + y + 90 = 180`

Subtract 90 from bot sides

`x + y = 90`

Make x the subject

`x = 90 - y`

Make y the subject

`y = 90 - x`

This implies that, subtract the known angle from 90 to get the unknown angle.

Assume
`x = 40`

We make use of:
`y = 90 - x`

`y = 90 - 40 = 50`

(b) Isosceles triangle

The sum of angles in an isosceles triangle is:

`x + y + y = 180` ---- y appear twice because the base angles are equal

`x + 2y = 180`

Make x the subject

`x = 180 - 2y`

Make y the subject

`y = (180 - x)/(2)`

Assume
`x = 40`, we make use of:

`y = (180 - x)/(2)`

`y = (180 - 40)/(2)`

`y = (140)/(2)`

`y = 70`

Assume
`y = 70`, we make use of:

`x = 180 - 2y`

`x = 180 - 2 * 70`

`x = 180 - 140`

`x = 40`