Question

I need help with this please its due today :(

Answer 1

`a) \ 6^2 * 6^3 = 6^(2+3) = 6^5 = 7776\\\\b)\ ((-3)^5 )/((-3)^2) = (-3)^(5-2) = (-3)^3 = -27\\\\c)\ [(-2)^3]^4 = (-2)^(3* 4) = (-2)^(12) = 4096 \\\\d)\ ((1)/(999))^0 = 1, anything \ raise \ to \ zero = 1\\\\e) \ ((4)/(3))^(-2) = 4^(-2) * 3^2 = (9)/(16)\\\\f) \ (2^5 * 2^9)/(2^(16)) = 2^(5+9-16) = 2^(-2) = (1)/(4)`