Question

Microwaves travel at the speed of light, 3x108m/s. When frequency of the microwaves is 9x109 Hz, quantitatively translate this information into their wavelength and period. Wavelength= 0.03m; period 1.1x10-10s , , Wavelength= 0.03m; period 1.1x10 -10 s, Wavelength= 0.03m; period 1.1x10-10s Wavelength= 0.03m; period 1.1x10 -10 s, Wavelength = 0.03cm; period 1.1x109s Wavelength = 0.03cm; period 1.1x10 9 s, Wavelength=0.03m; period 1.1x1010s

Answer 1

Step-by-step explanation:

Given that,

The frequency of microwaves,
`f=9* 10^9\ Hz`

The time period of the wave is :

`t=(1)/(f)\\\\t=(1)/(9* 10^9)\\\\t=1.1* 10^(-10)\ s`

Let
`\lambda` is the wavelength of the wave. We know that,

`v=f\lambda\\\\\lambda=(v)/(f)`

Put all the values,

`\lambda=(3* 10^8)/(9* 10^(9))\\\\\lambda=0.03\ m`

Hence, this is the required solution.