Question

Un cuerpo con un peso de magnitud igual a 200 N cuelga sobre dos cuerdas que forman un ángulo de 140° entre ellas. Determina la magnitud de la fuerza que ejerce cada cuerda sobre el cuerpo.

Answer 1

T = 292.4 N

Step-by-step explanation:

For this exercise we must use the translational equilibrium condition

∑ F = 0

Since force is a vector magnitude, the easiest way

Since the angle between the two forces is 140, the angle from the vertical is half tea = 70

cos θ = T_y / T

sin θ = Tₓ / T

T_y = T cos 70

Tₓ = T sin 70

X axis

Tₓ₁-Tₓ₂ = 0

Tₓ₁ = Tₓ₂

Y axis

T_y + T_y - W = 0

2 T cos 70 = W

T =
`(W)/(2 \ cos 70)`

let's calculate

T = 200/2 cos 70

T = 292.4 N