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What is the probability that a randomly selected student who lives in Nebraska plans to stay in his or her home state after graduation? Round your answer to the nearest hundredth.

User Josoler
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1 Answer

1 vote

Answer:


P (Yes | Nebraska) = 0.10

Explanation:

Given

See attachment for contingency table

Required


P (Yes | Nebraska)

From the contingency table, we have:


P (Yes\ n\ Nebraska) = 0.044


P (No\ n\ Nebraska) = 0.400

The required can be represented as:


P (Yes | Nebraska) = (P(Yes\ n\ Nebraska))/(P(Nebraska))

Where


P (Nebraska) = P (No\ n\ Nebraska) +P (Yes\ n\ Nebraska)

So, we have:


P (Nebraska) = 0.400 + 0.044


P (Nebraska) = 0.444

So, we have:


P (Yes | Nebraska) = (P(Yes\ n\ Nebraska))/(P(Nebraska))


P (Yes | Nebraska) = (0.044)/(0.444)


P (Yes | Nebraska) = 0.10 --- approximated

What is the probability that a randomly selected student who lives in Nebraska plans-example-1
User Ricard
by
7.4k points

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