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A bag contains 8 red M&Ms, 12 blue M&Ms, 3 brown M&Ms, and 7 green M&Ms. An M&M is picked at random from the bag. What is the probability of getting the first color M&M, eating it, then grabbing the second
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A bag contains 8 red M&Ms, 12 blue M&Ms, 3 brown M&Ms, and 7 green M&Ms. An M&M is picked at random from the bag. What is the probability of getting the first color M&M, eating it, then grabbing the second color? Green, then another green:

User Yaobin Then
by
7.0k points

1 Answer

2 votes

Answer:

7/145

Explanation:

7/30x6/29=42/870 = 7/145

User Engineforce
by
8.9k points
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