Answer:
H0 : μ1 - μ2 = 0
H0 : μ1 - μ2 > 0
Test statistic = 3.96
Critical value = 1.67
Reject H0
We can conclude that there is significant evidence to support the claim that geese do travel more Than pelicans
Explanation:
M= xbar1 = 191 ; M = xbar2 = 190 miles
n1 = 61 n2 = 61
s = 1.429 ; s2 = 1.355
Hypothesis :
H0 : μ1 - μ2 = 0
H0 : μ1 - μ2 > 0
Test statistic :
(x1 - x2) ÷ √[(s1²/n1) + (s2²/n2)]
(191 - 190) ÷ √[(1.429²/61) + (1.355²/61)]
1 ÷ √[(0.0334760) + (0.0300987)]
1 ÷ √0.0635747
1 ÷ 0.2521402
= 3.966
Degree of freedom :
df = n - 1
df = 61 - 1 = 60
Critical value :
Tcritical at 0.05%, df = 60
Tcritical = 1.67
Decision region:
Reject H0 if Tstatistic > Tcritical
Since ;
3.96 > 1.67 ; We reject H0
We can conclude that there is significant evidence to support the claim that geese do travel more Than pelicans