Question

Given you or a person holding a kite string 100 feet long write and draw what the height or altitude the kite is off the ground if the angle of elevation is 49 HELP!

Answer 1

Answer:
`75.47\ ft`

Explanation:

Given

String of the kite is
`l=100\ ft`

Angle of elevation
`\theta=49^(\circ)`

suppose altitude of the kite is h

from the figure, we can write

`\Rightarrow \sin 49^(\circ)=(h)/(100)\\\\\Rightarrow h=100\sin 49^(\circ)\\\\\Rightarrow h=75.47\ ft`

Thus, the altitude of the kite is
`75.47\ ft`