Answer:
The odds, in the most simplified form, are 7 to 3 against a randomly selected 18- to 34-year-old having cursed at his or her computer.
Explanation:
Given
---- proportion that cursed their computer
Required
Odds against the selected
Using the complement formula, the proportion that the selected has not cursed at their computer is:



So, the odds against the selected is:


Divide by 10%
