As triangle is right angled, we can possibly use the Pythagoras theroam.
By pythgoras theoram;
= H² = B² + P²
= 10² = x² + x²
= 10² = x⁴
=⁴√ 10² = x
= 10²×¼ = x
= 10½ = x
= √10 = x
= 3.16 = x
So the value of x is 3.16 cm
(Hypotenuse)² = (Base)²+ (Perpendicular)²
Taking, Hypotenuse As H
Base As B
Perpendicular As P
_________________________
H= 10cm
B= x cm
P= x cm
__________
H²= B²+P²
10²= x²+x²
=> 100= 2x²
=> √100= 2x
=> 10=2x
=> x=10/2
=> x= 5
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