Answer:
D.(3, 3)
Explanation:
The equation of a straight line is given as:
y = mx + c;
where x, y are variables, m is the slope of the line, c is the y intercept.
From the graph, we can see that line 1 passes through (6,0) and (0,6).
The equation of line 1 is given as:
![y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)\\\\y-0=(6-0)/(0-6) (x-6)\\\\y=-x + 6\ \ \ (1)](https://img.qammunity.org/2022/formulas/mathematics/college/3o3f3hezknj93dtcqnshshu5sp5hwrvkqm.png)
Line 2 passes through (6, 5) and (0, 1)
The equation of line 2 is given as:
![y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)\\\\y-5=(1-5)/(0-6) (x-6)\\\\y=(2)/(3)x + 1\ \ \ (2)](https://img.qammunity.org/2022/formulas/mathematics/college/6tms0tu4dntnuipz9mgql2s1mnt0bzkjhg.png)
To get the coordinates of the intersection of the two lines, we solve equation 1 and 2 simultaneously using a calculator. This gives:
x = 3, y = 3
Therefore the two lines meet at (3, 3)