Question

Please help me _/\_
Thank you :)​

Answer 1

Make equations first

Consider bigger number is X and smaller number is Y

condition 1,

3X+3Y = 34----------eq 1

condition 2,

2X-5Y = 9-------------eq 2

multiply eq 1 by 2 and eq 2 by 3,

6X+6Y = 68

6X-15Y = 27

Substracting above equation,

21Y = 41

Y = 41/21

Substituting Value of Y in eq 1,

3X+3×41/21 = 34

3X = 34-41/7

3X = (238-41)/7

3X = 197/7

X = 197/21

Hence X = 197/21 and Y = 41/21

Answer 2

Solution given:

let smaller number be a and bigger be b.

According to the question;

2a+3b=34.......[1]

2b-5a=9

5a-2b=-9.........[2]

Multiplying equation 1 by 5 and equation 2by 2 and subtracting equation we get

10a+15b=34*5

10a -4b=-9*2

- +. +.

19a=188

a=188/19

substituting value of a in equation 1

2*188/19+3b=34

3b=34-376/19

b=270/19*1/3

b=90/19

188/19 and 90/19 is a required number.