Question

If the solubility of a gas in water is 3.0 g/L when the pressure of the gas above the water is 4.0 atm, what is the pressure of the gas above the water when the solubility of the gas is 1.0 g/L

Answer 1

`P_2=1.3atm`

Step-by-step explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to model the solubility and pressure of the gas, by knowing that the greater the pressure, the greater the solubility, so that the suitable equation is:

`(P_2)/(s_2)=(P_1)/(s_1)`

In such a way, we will be able to calculate the pressure of the gas by solving for P2 as shown below:

`P_2=(P_1*s_2)/(s_1) \\\\`

And finally plug in the given data to obtain:

`P_2=(4.0atm*1.0g/L)/(3.0g/L)\\\\P_2=1.3atm`

Regards!