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2 votes
2 votes
How many mL of 8.00M HCl solution are needed to make a dilution with a final volume of 2,500.ml, and a

concentration of HC-0.333M?

User Ravinder Singh
by
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1 Answer

5 votes
5 votes

Answer:

104.1 mL

Step-by-step explanation:

c1V1 = c2V2

V1 = c2V2/c1 = (0.333 M×2500 mL)/8.00 M

V1 = 104.1 mL

User Nuageux
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