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How many grams of BaPO3 are present in a 3.8 mole sample?
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3 votes
How many grams of BaPO3 are present in a 3.8 mole sample?

User James Vickers
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1 Answer

3 votes

Step-by-step explanation:

M(Bapo3) = 216m/mol

n = 3.8 mole

m = M × n = 216 × 3.8 = 820.8g

User Zin Kun
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