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How many atoms are present in 14 g of iron

User Linden
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1 Answer

1 vote

Answer:

1.51 × 10²³ atoms

Step-by-step explanation:

First, we convert 14g of iron (Fe) to moles using the formula below:

mole = mass ÷ molar mass

Molar mass of Fe = 55.85g/mol

mole = 14g ÷ 55.85g/mol

mole = 0.251mol

The number of atoms in 0.251 mol of Fe is calculated as follows:

number of atoms = n × nA

Where;

n = number of moles

nA = Avagadros number (6.02 × 10²³)

number of atoms = 0.251 × 6.02 × 10²³

number of atoms = 1.51 × 10²³ atoms.

User Fillobotto
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