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Solve the missing elements for each problem. Use 3.14 for π. Area π r² ; C = π D​

Solve the missing elements for each problem. Use 3.14 for π. Area π r² ; C = π D​-example-1
User Rafael
by
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2 Answers

7 votes

Answer: Solve the missing elements for each problem. Use 3.14 for π. Area π r² ; C = π D​

Explanation:

1. Radius = 32/2 = 16 inches

Diameter = 32 inches

Circumference = 3.14 × 32 = 100.48 inches

Area = 3.14 × 256 = 803.84 inches

2. Radius :- 40 / 2 = 20 inches

Diameter = 40 inches

Circumference = 3.14 × 40 = 125.6 inches

Area = 3.14 × 20 × 20 = 1256 inches

3. Radius = 28 / 2 = 14 inches

Diameter = 28 inches

Circumference = 3.14 × 28 = 87.92 inches

Area = 3.14 × 14 × 14 = 615.44 inches

4. Radius = 18/2 = 9 inches

Diameter = 18 inches

Circumference = 3.14 × 18 = 56.52 inches

Area = 3.14 × 9 × 9 = 254.34 inches

5. Radius = 5 inches

Diameter = 5 × 2 = 10 inches

Circumference = 3.14 × 10 = 31.4 inches

Area = 3.14 × 5 × 5 = 78.5 inches

6. Radius = 2 inches

Diameter = 2 × 2 = 4 inches

Circumference = 3.14 × 4 = 12.56 inches

Area = 3.14 × 2 × 2 = 12.56 inches

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User Tylisha
by
5.0k points
6 votes

Answer and Solution

1. Radius = 32/2 = 16 inches

Diameter = 32 inches

Circumference = 3.14 × 32 = 100.48 inches

Area = 3.14 × 256 = 803.84 inches

2. Radius :- 40 / 2 = 20 inches

Diameter = 40 inches

Circumference = 3.14 × 40 = 125.6 inches

Area = 3.14 × 20 × 20 = 1256 inches

3. Radius = 28 / 2 = 14 inches

Diameter = 28 inches

Circumference = 3.14 × 28 = 87.92 inches

Area = 3.14 × 14 × 14 = 615.44 inches

4. Radius = 18/2 = 9 inches

Diameter = 18 inches

Circumference = 3.14 × 18 = 56.52 inches

Area = 3.14 × 9 × 9 = 254.34 inches

5. Radius = 5 inches

Diameter = 5 × 2 = 10 inches

Circumference = 3.14 × 10 = 31.4 inches

Area = 3.14 × 5 × 5 = 78.5 inches

6. Radius = 2 inches

Diameter = 2 × 2 = 4 inches

Circumference = 3.14 × 4 = 12.56 inches

Area = 3.14 × 2 × 2 = 12.56 inches

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User Pbathala
by
4.6k points