Question

3.00 L of a gas is collected at 150 K and then allowed to expand to

15.0 L. What must the new temperature be in degrees C in order to
maintain the same pressure (as required by Charles' Law)?

Answer 1

477 ºC

Step-by-step explanation:

on an isobaric process, an increase on the volume implies an increase on the temperature:

V1/T1 = V2/T2

T2 = V2T1/V1 = 15.0 L×150 K/3.00 L = 750 K

t/ºC = T/K - 273 = 750 K/K - 273

t = 477 ºC

V1: initial volume

T1: initial temperature

V2: final volume

T2: final temperature