Question

What is the equation for the reaction between ethanoic acid and butanol in the presence of H2SO4?

Answer 1

`CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O`

Step-by-step explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize this is a question about esterification, process whereby a carboxylic acid and an alcohol react to produce water an an ester, we can set it up as shown below:

`CH_3COOH+CH_3CH_2CH_2CH_2OH`

For the reaction between ethanoic acid and butanol; and therefore, the products side is:

`CH_3COOCH_2CH_2CH_2CH_3+H_2O`

It means that the overall equation is:

`CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O`

And the ester product is butyl ethanoate.

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