Question

What is the equation of the line that is parallel to y=1/3x+4 and passes through (-3, 1);

A y=-3x – 8
B y= 3x + 10
C y=-1/3x
D y= 1/3x+2

Answer 1

Explanation:

`y = (1)/(3) x +4` ,
`slope, m_1 = (1)/(3)`

Let the slope of the new line be
`m_2`

Since the lines are parallel ,
`m_1 = m_2`

`m_2 = (1)/(3)`

`(x_1, y_1) = (-3, 1) \ , \ m_2 = (1)/(3)\\\\Equation \ of \ the \ new \ line : (y - y_1) = m(x - x_1)`

`y - 1 = (1)/(3)(x -(-3)) \\\\y - 1 = (1)/(3)(x +3)\\\\y - 1 =\frac{1} {3}x + 1 \\\\y = (1)/(3)x + 2`