Question

The lengths of the 2 diagonal of a rhombus are 24cm and 32cm what is the length of one side of the rhombus. ​

Answer 1

side=√(24/2)²+(32/2)²

=√12²+16²

=√400

= 20

Answer 2

`height = (24)/(2) = 12 \: cm \\ adjacent = (32)/(2) = 16 \: cm`

We get a triangle of height 12 cm and adjacent 16 cm

`side = \sqrt{ {12}^(2) + {16}^(2) } \\ = √(400) \\ = 20 \: cm`