Calculate the mass of O2 produced after 20.0 grams of KClO3 have reacted?

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asked Oct 1, 2022 198k views

4 votes

Calculate the mass of O2 produced after 20.0 grams of KClO3 have reacted?

Chemistry
high-school

Offler asked

by Offler

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1 Answer

5 votes

Answer:

$RFM \: of \: potassium \: chlorate = (39 + 35.5 + (16 * 3)) = 122.5 \: g \\ 122.5 \: g \: of \: potassium \: chlorate \: produce \: (16 * 3) \: g \: of \: oxygen \\ 20.0 \: g \: of \: potassium \: chlorate \: will \: produce \: (((20.0 * 16 * 3))/(122.5) ) \: g \\ = 7.84 \: g \: of \: oxygen$