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HELP, PLEASE I NEED IT! π∆π

Applying the 30-60-90 Theorem, Solve this.​

HELP, PLEASE I NEED IT! π∆π Applying the 30-60-90 Theorem, Solve this.​-example-1
User Wires
by
5.7k points

2 Answers

4 votes

Answer:

Explanation:

take 30 degree as reference angle

using sin rule

sin 30=opposite/hypotenuse

1/2=12/y(do cross multiplication?

12*2=y

24=y

for x

using pythagoras theorem

H^2=P^2+B^2

24^2=12^2+B^2

576=144+B^2

576-144=B^2

432=B^2


√(432)=B

12
√(3)=B

12
√(3)=X1

User Kalendae
by
6.1k points
1 vote

Answer:

'y' would be 24

'x' would be 12
√(3)

Explanation:

the ratio of sides in a 30-60-90 triangle is, respectively, 1 :
√(3) : 2

so the side across from the 60 degree angle is
√(3) times the side of the 30°

the side across from the 90 degree angle is double the side of the 30°

so in this problem 'y' would be 24 and 'x' would be 12
√(3)

User Igor Yalovoy
by
4.7k points