A 75 kg refrigerator is located on the 70th floor of skyscraper (300 meters above ground). What is the potential energy of the refrigerator. (PE=MGH(G=9.8M/S²)

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asked Feb 26, 2022 49.3k views

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A 75 kg refrigerator is located on the 70th floor of skyscraper (300 meters above ground). What is the potential energy of the refrigerator. (PE=MGH(G=9.8M/S²)

Physics
high-school

LoganMzz asked

by LoganMzz

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2 Answers

6 votes

Answer:

googli moogli

Step-by-step explanation:

Arun Mohan answered Feb 27, 2022

by Arun Mohan

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1 vote

Answer:

220,500 Joules

Step-by-step explanation:

PE = (75 kg) x (9.8
m/s^(2) ) x (300 m)

PE = (735) x (300)

PE = 220,500 Joules

Musaffir Lp answered Mar 2, 2022

by Musaffir Lp

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