Question

Theodore needs to mix a 10% saline solution with a 60% saline solution to create 200 milliliters of a 12.5% solution. How many milliliters of each solution must Theodore use

Answer 1

x = 10% saline solution = 190 mililiters

y = 60% saline solution = 10 mililiters

Explanation:

Theodore needs to mix a 10% saline solution with a 60% saline solution to create 200 milliliters of a 12.5% solution. How many milliliters of each solution must Theodore use

Let

x = 10% saline solution

y = 60% saline solution

x + y = 200

x = 200 - y

10% × x + 60% × y = 200 × 12.5 %

Hence:.0.1x + 0.6y = 25

Substituting 200 - y for x

0.1(200 - y) + 0.6y = 25

20 - 0.1y + 0.6y = 25

- 0.1y + 0.6y = 25 - 20

0.5y = 5

y = 5/0.5

y = 10 milliliters

Solving for x

x = 200 - y

x = 200 - 10

x = 190 mililiters